B38A hexadecimal to binary

Here we will show you how to convert the hexadecimal number B38A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B38A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B38A by 16⁰, multiply the second to last digit in B38A by 16¹, multiply the third to last digit in B38A by 16², multiply the fourth to last digit in B38A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
8 × 16¹ = 128
3 × 16² = 768
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 128 + 768 + 45056 = 45962

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

45962 ÷ 2 = 22981 with 0 remainder
22981 ÷ 2 = 11490 with 1 remainder
11490 ÷ 2 = 5745 with 0 remainder
5745 ÷ 2 = 2872 with 1 remainder
2872 ÷ 2 = 1436 with 0 remainder
1436 ÷ 2 = 718 with 0 remainder
718 ÷ 2 = 359 with 0 remainder
359 ÷ 2 = 179 with 1 remainder
179 ÷ 2 = 89 with 1 remainder
89 ÷ 2 = 44 with 1 remainder
44 ÷ 2 = 22 with 0 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B38A hexadecimal to binary:

B38A hexadecimal = 1011001110001010 binary

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B38B hexadecimal to binary
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