B0AB hexadecimal to binary




Here we will show you how to convert the hexadecimal number B0AB to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert B0AB from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B0AB by 16⁰, multiply the second to last digit in B0AB by 16¹, multiply the third to last digit in B0AB by 16², multiply the fourth to last digit in B0AB by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
A × 16¹ = 160
0 × 16² = 0
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 160 + 0 + 45056 = 45227

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

45227 ÷ 2 = 22613 with 1 remainder
22613 ÷ 2 = 11306 with 1 remainder
11306 ÷ 2 = 5653 with 0 remainder
5653 ÷ 2 = 2826 with 1 remainder
2826 ÷ 2 = 1413 with 0 remainder
1413 ÷ 2 = 706 with 1 remainder
706 ÷ 2 = 353 with 0 remainder
353 ÷ 2 = 176 with 1 remainder
176 ÷ 2 = 88 with 0 remainder
88 ÷ 2 = 44 with 0 remainder
44 ÷ 2 = 22 with 0 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B0AB hexadecimal to binary:

B0AB hexadecimal = 1011000010101011 binary


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B0AC hexadecimal to binary
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