AA58 hexadecimal to binary

Here we will show you how to convert the hexadecimal number AA58 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert AA58 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in AA58 by 16⁰, multiply the second to last digit in AA58 by 16¹, multiply the third to last digit in AA58 by 16², multiply the fourth to last digit in AA58 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
5 × 16¹ = 80
A × 16² = 2560
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 80 + 2560 + 40960 = 43608

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

43608 ÷ 2 = 21804 with 0 remainder
21804 ÷ 2 = 10902 with 0 remainder
10902 ÷ 2 = 5451 with 0 remainder
5451 ÷ 2 = 2725 with 1 remainder
2725 ÷ 2 = 1362 with 1 remainder
1362 ÷ 2 = 681 with 0 remainder
681 ÷ 2 = 340 with 1 remainder
340 ÷ 2 = 170 with 0 remainder
170 ÷ 2 = 85 with 0 remainder
85 ÷ 2 = 42 with 1 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to AA58 hexadecimal to binary:

AA58 hexadecimal = 1010101001011000 binary

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AA59 hexadecimal to binary
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