A9DB hexadecimal to binary

Here we will show you how to convert the hexadecimal number A9DB to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A9DB from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A9DB by 16⁰, multiply the second to last digit in A9DB by 16¹, multiply the third to last digit in A9DB by 16², multiply the fourth to last digit in A9DB by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
D × 16¹ = 208
9 × 16² = 2304
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 208 + 2304 + 40960 = 43483

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

43483 ÷ 2 = 21741 with 1 remainder
21741 ÷ 2 = 10870 with 1 remainder
10870 ÷ 2 = 5435 with 0 remainder
5435 ÷ 2 = 2717 with 1 remainder
2717 ÷ 2 = 1358 with 1 remainder
1358 ÷ 2 = 679 with 0 remainder
679 ÷ 2 = 339 with 1 remainder
339 ÷ 2 = 169 with 1 remainder
169 ÷ 2 = 84 with 1 remainder
84 ÷ 2 = 42 with 0 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A9DB hexadecimal to binary:

A9DB hexadecimal = 1010100111011011 binary

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A9DC hexadecimal to binary
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