A9BA hexadecimal to binary

Here we will show you how to convert the hexadecimal number A9BA to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A9BA from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A9BA by 16⁰, multiply the second to last digit in A9BA by 16¹, multiply the third to last digit in A9BA by 16², multiply the fourth to last digit in A9BA by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
B × 16¹ = 176
9 × 16² = 2304
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 176 + 2304 + 40960 = 43450

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

43450 ÷ 2 = 21725 with 0 remainder
21725 ÷ 2 = 10862 with 1 remainder
10862 ÷ 2 = 5431 with 0 remainder
5431 ÷ 2 = 2715 with 1 remainder
2715 ÷ 2 = 1357 with 1 remainder
1357 ÷ 2 = 678 with 1 remainder
678 ÷ 2 = 339 with 0 remainder
339 ÷ 2 = 169 with 1 remainder
169 ÷ 2 = 84 with 1 remainder
84 ÷ 2 = 42 with 0 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A9BA hexadecimal to binary:

A9BA hexadecimal = 1010100110111010 binary

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A9BB hexadecimal to binary
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