A90B hexadecimal to binary

Here we will show you how to convert the hexadecimal number A90B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A90B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A90B by 16⁰, multiply the second to last digit in A90B by 16¹, multiply the third to last digit in A90B by 16², multiply the fourth to last digit in A90B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
0 × 16¹ = 0
9 × 16² = 2304
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 0 + 2304 + 40960 = 43275

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

43275 ÷ 2 = 21637 with 1 remainder
21637 ÷ 2 = 10818 with 1 remainder
10818 ÷ 2 = 5409 with 0 remainder
5409 ÷ 2 = 2704 with 1 remainder
2704 ÷ 2 = 1352 with 0 remainder
1352 ÷ 2 = 676 with 0 remainder
676 ÷ 2 = 338 with 0 remainder
338 ÷ 2 = 169 with 0 remainder
169 ÷ 2 = 84 with 1 remainder
84 ÷ 2 = 42 with 0 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A90B hexadecimal to binary:

A90B hexadecimal = 1010100100001011 binary

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