A88A hexadecimal to binary

Here we will show you how to convert the hexadecimal number A88A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A88A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A88A by 16⁰, multiply the second to last digit in A88A by 16¹, multiply the third to last digit in A88A by 16², multiply the fourth to last digit in A88A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
8 × 16¹ = 128
8 × 16² = 2048
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 128 + 2048 + 40960 = 43146

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

43146 ÷ 2 = 21573 with 0 remainder
21573 ÷ 2 = 10786 with 1 remainder
10786 ÷ 2 = 5393 with 0 remainder
5393 ÷ 2 = 2696 with 1 remainder
2696 ÷ 2 = 1348 with 0 remainder
1348 ÷ 2 = 674 with 0 remainder
674 ÷ 2 = 337 with 0 remainder
337 ÷ 2 = 168 with 1 remainder
168 ÷ 2 = 84 with 0 remainder
84 ÷ 2 = 42 with 0 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A88A hexadecimal to binary:

A88A hexadecimal = 1010100010001010 binary

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A88B hexadecimal to binary
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