A84B hexadecimal to binary

Here we will show you how to convert the hexadecimal number A84B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A84B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A84B by 16⁰, multiply the second to last digit in A84B by 16¹, multiply the third to last digit in A84B by 16², multiply the fourth to last digit in A84B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
4 × 16¹ = 64
8 × 16² = 2048
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 64 + 2048 + 40960 = 43083

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

43083 ÷ 2 = 21541 with 1 remainder
21541 ÷ 2 = 10770 with 1 remainder
10770 ÷ 2 = 5385 with 0 remainder
5385 ÷ 2 = 2692 with 1 remainder
2692 ÷ 2 = 1346 with 0 remainder
1346 ÷ 2 = 673 with 0 remainder
673 ÷ 2 = 336 with 1 remainder
336 ÷ 2 = 168 with 0 remainder
168 ÷ 2 = 84 with 0 remainder
84 ÷ 2 = 42 with 0 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A84B hexadecimal to binary:

A84B hexadecimal = 1010100001001011 binary

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