A73B hexadecimal to binary

Here we will show you how to convert the hexadecimal number A73B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A73B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A73B by 16⁰, multiply the second to last digit in A73B by 16¹, multiply the third to last digit in A73B by 16², multiply the fourth to last digit in A73B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
3 × 16¹ = 48
7 × 16² = 1792
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 48 + 1792 + 40960 = 42811

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

42811 ÷ 2 = 21405 with 1 remainder
21405 ÷ 2 = 10702 with 1 remainder
10702 ÷ 2 = 5351 with 0 remainder
5351 ÷ 2 = 2675 with 1 remainder
2675 ÷ 2 = 1337 with 1 remainder
1337 ÷ 2 = 668 with 1 remainder
668 ÷ 2 = 334 with 0 remainder
334 ÷ 2 = 167 with 0 remainder
167 ÷ 2 = 83 with 1 remainder
83 ÷ 2 = 41 with 1 remainder
41 ÷ 2 = 20 with 1 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A73B hexadecimal to binary:

A73B hexadecimal = 1010011100111011 binary

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