A39B hexadecimal to binary

Here we will show you how to convert the hexadecimal number A39B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A39B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A39B by 16⁰, multiply the second to last digit in A39B by 16¹, multiply the third to last digit in A39B by 16², multiply the fourth to last digit in A39B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
9 × 16¹ = 144
3 × 16² = 768
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 144 + 768 + 40960 = 41883

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

41883 ÷ 2 = 20941 with 1 remainder
20941 ÷ 2 = 10470 with 1 remainder
10470 ÷ 2 = 5235 with 0 remainder
5235 ÷ 2 = 2617 with 1 remainder
2617 ÷ 2 = 1308 with 1 remainder
1308 ÷ 2 = 654 with 0 remainder
654 ÷ 2 = 327 with 0 remainder
327 ÷ 2 = 163 with 1 remainder
163 ÷ 2 = 81 with 1 remainder
81 ÷ 2 = 40 with 1 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A39B hexadecimal to binary:

A39B hexadecimal = 1010001110011011 binary

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