A34A hexadecimal to binary

Here we will show you how to convert the hexadecimal number A34A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A34A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A34A by 16⁰, multiply the second to last digit in A34A by 16¹, multiply the third to last digit in A34A by 16², multiply the fourth to last digit in A34A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
4 × 16¹ = 64
3 × 16² = 768
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 64 + 768 + 40960 = 41802

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

41802 ÷ 2 = 20901 with 0 remainder
20901 ÷ 2 = 10450 with 1 remainder
10450 ÷ 2 = 5225 with 0 remainder
5225 ÷ 2 = 2612 with 1 remainder
2612 ÷ 2 = 1306 with 0 remainder
1306 ÷ 2 = 653 with 0 remainder
653 ÷ 2 = 326 with 1 remainder
326 ÷ 2 = 163 with 0 remainder
163 ÷ 2 = 81 with 1 remainder
81 ÷ 2 = 40 with 1 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A34A hexadecimal to binary:

A34A hexadecimal = 1010001101001010 binary

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A34B hexadecimal to binary
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