A2B8 hexadecimal to binary

Here we will show you how to convert the hexadecimal number A2B8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A2B8 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A2B8 by 16⁰, multiply the second to last digit in A2B8 by 16¹, multiply the third to last digit in A2B8 by 16², multiply the fourth to last digit in A2B8 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
B × 16¹ = 176
2 × 16² = 512
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 176 + 512 + 40960 = 41656

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

41656 ÷ 2 = 20828 with 0 remainder
20828 ÷ 2 = 10414 with 0 remainder
10414 ÷ 2 = 5207 with 0 remainder
5207 ÷ 2 = 2603 with 1 remainder
2603 ÷ 2 = 1301 with 1 remainder
1301 ÷ 2 = 650 with 1 remainder
650 ÷ 2 = 325 with 0 remainder
325 ÷ 2 = 162 with 1 remainder
162 ÷ 2 = 81 with 0 remainder
81 ÷ 2 = 40 with 1 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A2B8 hexadecimal to binary:

A2B8 hexadecimal = 1010001010111000 binary

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A2B9 hexadecimal to binary
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