A245 hexadecimal to binary

Here we will show you how to convert the hexadecimal number A245 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A245 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A245 by 16⁰, multiply the second to last digit in A245 by 16¹, multiply the third to last digit in A245 by 16², multiply the fourth to last digit in A245 by 16³, and so on, until all the digits are used.

5 × 16⁰ = 5
4 × 16¹ = 64
2 × 16² = 512
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

5 + 64 + 512 + 40960 = 41541

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

41541 ÷ 2 = 20770 with 1 remainder
20770 ÷ 2 = 10385 with 0 remainder
10385 ÷ 2 = 5192 with 1 remainder
5192 ÷ 2 = 2596 with 0 remainder
2596 ÷ 2 = 1298 with 0 remainder
1298 ÷ 2 = 649 with 0 remainder
649 ÷ 2 = 324 with 1 remainder
324 ÷ 2 = 162 with 0 remainder
162 ÷ 2 = 81 with 0 remainder
81 ÷ 2 = 40 with 1 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A245 hexadecimal to binary:

A245 hexadecimal = 1010001001000101 binary

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A246 hexadecimal to binary
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