A17A hexadecimal to binary

Here we will show you how to convert the hexadecimal number A17A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A17A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A17A by 16⁰, multiply the second to last digit in A17A by 16¹, multiply the third to last digit in A17A by 16², multiply the fourth to last digit in A17A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
7 × 16¹ = 112
1 × 16² = 256
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 112 + 256 + 40960 = 41338

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

41338 ÷ 2 = 20669 with 0 remainder
20669 ÷ 2 = 10334 with 1 remainder
10334 ÷ 2 = 5167 with 0 remainder
5167 ÷ 2 = 2583 with 1 remainder
2583 ÷ 2 = 1291 with 1 remainder
1291 ÷ 2 = 645 with 1 remainder
645 ÷ 2 = 322 with 1 remainder
322 ÷ 2 = 161 with 0 remainder
161 ÷ 2 = 80 with 1 remainder
80 ÷ 2 = 40 with 0 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A17A hexadecimal to binary:

A17A hexadecimal = 1010000101111010 binary

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A17B hexadecimal to binary
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