A11C hexadecimal to binary

Here we will show you how to convert the hexadecimal number A11C to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert A11C from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in A11C by 16⁰, multiply the second to last digit in A11C by 16¹, multiply the third to last digit in A11C by 16², multiply the fourth to last digit in A11C by 16³, and so on, until all the digits are used.

C × 16⁰ = 12
1 × 16¹ = 16
1 × 16² = 256
A × 16³ = 40960

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

12 + 16 + 256 + 40960 = 41244

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

41244 ÷ 2 = 20622 with 0 remainder
20622 ÷ 2 = 10311 with 0 remainder
10311 ÷ 2 = 5155 with 1 remainder
5155 ÷ 2 = 2577 with 1 remainder
2577 ÷ 2 = 1288 with 1 remainder
1288 ÷ 2 = 644 with 0 remainder
644 ÷ 2 = 322 with 0 remainder
322 ÷ 2 = 161 with 0 remainder
161 ÷ 2 = 80 with 1 remainder
80 ÷ 2 = 40 with 0 remainder
40 ÷ 2 = 20 with 0 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to A11C hexadecimal to binary:

A11C hexadecimal = 1010000100011100 binary

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