9F28 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9F28 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9F28 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9F28 by 16⁰, multiply the second to last digit in 9F28 by 16¹, multiply the third to last digit in 9F28 by 16², multiply the fourth to last digit in 9F28 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
2 × 16¹ = 32
F × 16² = 3840
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 32 + 3840 + 36864 = 40744

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

40744 ÷ 2 = 20372 with 0 remainder
20372 ÷ 2 = 10186 with 0 remainder
10186 ÷ 2 = 5093 with 0 remainder
5093 ÷ 2 = 2546 with 1 remainder
2546 ÷ 2 = 1273 with 0 remainder
1273 ÷ 2 = 636 with 1 remainder
636 ÷ 2 = 318 with 0 remainder
318 ÷ 2 = 159 with 0 remainder
159 ÷ 2 = 79 with 1 remainder
79 ÷ 2 = 39 with 1 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9F28 hexadecimal to binary:

9F28 hexadecimal = 1001111100101000 binary

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9F29 hexadecimal to binary
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