9DFC hexadecimal to binary




Here we will show you how to convert the hexadecimal number 9DFC to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert 9DFC from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9DFC by 16⁰, multiply the second to last digit in 9DFC by 16¹, multiply the third to last digit in 9DFC by 16², multiply the fourth to last digit in 9DFC by 16³, and so on, until all the digits are used.

C × 16⁰ = 12
F × 16¹ = 240
D × 16² = 3328
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

12 + 240 + 3328 + 36864 = 40444

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

40444 ÷ 2 = 20222 with 0 remainder
20222 ÷ 2 = 10111 with 0 remainder
10111 ÷ 2 = 5055 with 1 remainder
5055 ÷ 2 = 2527 with 1 remainder
2527 ÷ 2 = 1263 with 1 remainder
1263 ÷ 2 = 631 with 1 remainder
631 ÷ 2 = 315 with 1 remainder
315 ÷ 2 = 157 with 1 remainder
157 ÷ 2 = 78 with 1 remainder
78 ÷ 2 = 39 with 0 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9DFC hexadecimal to binary:

9DFC hexadecimal = 1001110111111100 binary


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