9D54 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9D54 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9D54 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9D54 by 16⁰, multiply the second to last digit in 9D54 by 16¹, multiply the third to last digit in 9D54 by 16², multiply the fourth to last digit in 9D54 by 16³, and so on, until all the digits are used.

4 × 16⁰ = 4
5 × 16¹ = 80
D × 16² = 3328
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

4 + 80 + 3328 + 36864 = 40276

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

40276 ÷ 2 = 20138 with 0 remainder
20138 ÷ 2 = 10069 with 0 remainder
10069 ÷ 2 = 5034 with 1 remainder
5034 ÷ 2 = 2517 with 0 remainder
2517 ÷ 2 = 1258 with 1 remainder
1258 ÷ 2 = 629 with 0 remainder
629 ÷ 2 = 314 with 1 remainder
314 ÷ 2 = 157 with 0 remainder
157 ÷ 2 = 78 with 1 remainder
78 ÷ 2 = 39 with 0 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9D54 hexadecimal to binary:

9D54 hexadecimal = 1001110101010100 binary

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9D55 hexadecimal to binary
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