
Here we will show you how to convert the hexadecimal number 9D1 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).
The four steps used to convert 9D1 from hexadecimal to binary are explained below.
Step 1)
Multiply the last digit in 9D1 by 16⁰, multiply the second to last digit in 9D1 by 16¹, multiply the third to last digit in 9D1 by 16², multiply the fourth to last digit in 9D1 by 16³, and so on, until all the digits are used.
1 × 16⁰ = 1
D × 16¹ = 208
9 × 16² = 2304
Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.
Step 2)
Next, we add up all the products we got from Step 1, like this:
1 + 208 + 2304 = 2513
Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.
2513 ÷ 2 = 1256 with 1 remainder
1256 ÷ 2 = 628 with 0 remainder
628 ÷ 2 = 314 with 0 remainder
314 ÷ 2 = 157 with 0 remainder
157 ÷ 2 = 78 with 1 remainder
78 ÷ 2 = 39 with 0 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder
Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9D1 hexadecimal to binary:
9D1 hexadecimal = 100111010001 binary
Hexadecimal to Binary Converter
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9D2 hexadecimal to binary
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