9C4B hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9C4B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9C4B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9C4B by 16⁰, multiply the second to last digit in 9C4B by 16¹, multiply the third to last digit in 9C4B by 16², multiply the fourth to last digit in 9C4B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
4 × 16¹ = 64
C × 16² = 3072
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 64 + 3072 + 36864 = 40011

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

40011 ÷ 2 = 20005 with 1 remainder
20005 ÷ 2 = 10002 with 1 remainder
10002 ÷ 2 = 5001 with 0 remainder
5001 ÷ 2 = 2500 with 1 remainder
2500 ÷ 2 = 1250 with 0 remainder
1250 ÷ 2 = 625 with 0 remainder
625 ÷ 2 = 312 with 1 remainder
312 ÷ 2 = 156 with 0 remainder
156 ÷ 2 = 78 with 0 remainder
78 ÷ 2 = 39 with 0 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9C4B hexadecimal to binary:

9C4B hexadecimal = 1001110001001011 binary

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9C4C hexadecimal to binary
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