9C0F hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9C0F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9C0F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9C0F by 16⁰, multiply the second to last digit in 9C0F by 16¹, multiply the third to last digit in 9C0F by 16², multiply the fourth to last digit in 9C0F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
0 × 16¹ = 0
C × 16² = 3072
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 0 + 3072 + 36864 = 39951

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

39951 ÷ 2 = 19975 with 1 remainder
19975 ÷ 2 = 9987 with 1 remainder
9987 ÷ 2 = 4993 with 1 remainder
4993 ÷ 2 = 2496 with 1 remainder
2496 ÷ 2 = 1248 with 0 remainder
1248 ÷ 2 = 624 with 0 remainder
624 ÷ 2 = 312 with 0 remainder
312 ÷ 2 = 156 with 0 remainder
156 ÷ 2 = 78 with 0 remainder
78 ÷ 2 = 39 with 0 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9C0F hexadecimal to binary:

9C0F hexadecimal = 1001110000001111 binary

Hexadecimal to Binary Converter
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