9C0 hexadecimal to binary




Here we will show you how to convert the hexadecimal number 9C0 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert 9C0 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9C0 by 16⁰, multiply the second to last digit in 9C0 by 16¹, multiply the third to last digit in 9C0 by 16², multiply the fourth to last digit in 9C0 by 16³, and so on, until all the digits are used.

0 × 16⁰ = 0
C × 16¹ = 192
9 × 16² = 2304

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

0 + 192 + 2304 = 2496

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

2496 ÷ 2 = 1248 with 0 remainder
1248 ÷ 2 = 624 with 0 remainder
624 ÷ 2 = 312 with 0 remainder
312 ÷ 2 = 156 with 0 remainder
156 ÷ 2 = 78 with 0 remainder
78 ÷ 2 = 39 with 0 remainder
39 ÷ 2 = 19 with 1 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9C0 hexadecimal to binary:

9C0 hexadecimal = 100111000000 binary


Hexadecimal to Binary Converter
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