9BD hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9BD to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9BD from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9BD by 16⁰, multiply the second to last digit in 9BD by 16¹, multiply the third to last digit in 9BD by 16², multiply the fourth to last digit in 9BD by 16³, and so on, until all the digits are used.

D × 16⁰ = 13
B × 16¹ = 176
9 × 16² = 2304

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

13 + 176 + 2304 = 2493

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

2493 ÷ 2 = 1246 with 1 remainder
1246 ÷ 2 = 623 with 0 remainder
623 ÷ 2 = 311 with 1 remainder
311 ÷ 2 = 155 with 1 remainder
155 ÷ 2 = 77 with 1 remainder
77 ÷ 2 = 38 with 1 remainder
38 ÷ 2 = 19 with 0 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9BD hexadecimal to binary:

9BD hexadecimal = 100110111101 binary

Hexadecimal to Binary Converter
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