9B30 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9B30 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9B30 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9B30 by 16⁰, multiply the second to last digit in 9B30 by 16¹, multiply the third to last digit in 9B30 by 16², multiply the fourth to last digit in 9B30 by 16³, and so on, until all the digits are used.

0 × 16⁰ = 0
3 × 16¹ = 48
B × 16² = 2816
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

0 + 48 + 2816 + 36864 = 39728

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

39728 ÷ 2 = 19864 with 0 remainder
19864 ÷ 2 = 9932 with 0 remainder
9932 ÷ 2 = 4966 with 0 remainder
4966 ÷ 2 = 2483 with 0 remainder
2483 ÷ 2 = 1241 with 1 remainder
1241 ÷ 2 = 620 with 1 remainder
620 ÷ 2 = 310 with 0 remainder
310 ÷ 2 = 155 with 0 remainder
155 ÷ 2 = 77 with 1 remainder
77 ÷ 2 = 38 with 1 remainder
38 ÷ 2 = 19 with 0 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9B30 hexadecimal to binary:

9B30 hexadecimal = 1001101100110000 binary

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9B31 hexadecimal to binary
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