9B23 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9B23 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9B23 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9B23 by 16⁰, multiply the second to last digit in 9B23 by 16¹, multiply the third to last digit in 9B23 by 16², multiply the fourth to last digit in 9B23 by 16³, and so on, until all the digits are used.

3 × 16⁰ = 3
2 × 16¹ = 32
B × 16² = 2816
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

3 + 32 + 2816 + 36864 = 39715

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

39715 ÷ 2 = 19857 with 1 remainder
19857 ÷ 2 = 9928 with 1 remainder
9928 ÷ 2 = 4964 with 0 remainder
4964 ÷ 2 = 2482 with 0 remainder
2482 ÷ 2 = 1241 with 0 remainder
1241 ÷ 2 = 620 with 1 remainder
620 ÷ 2 = 310 with 0 remainder
310 ÷ 2 = 155 with 0 remainder
155 ÷ 2 = 77 with 1 remainder
77 ÷ 2 = 38 with 1 remainder
38 ÷ 2 = 19 with 0 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9B23 hexadecimal to binary:

9B23 hexadecimal = 1001101100100011 binary

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9B24 hexadecimal to binary
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