9A08 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 9A08 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 9A08 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 9A08 by 16⁰, multiply the second to last digit in 9A08 by 16¹, multiply the third to last digit in 9A08 by 16², multiply the fourth to last digit in 9A08 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
0 × 16¹ = 0
A × 16² = 2560
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 0 + 2560 + 36864 = 39432

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

39432 ÷ 2 = 19716 with 0 remainder
19716 ÷ 2 = 9858 with 0 remainder
9858 ÷ 2 = 4929 with 0 remainder
4929 ÷ 2 = 2464 with 1 remainder
2464 ÷ 2 = 1232 with 0 remainder
1232 ÷ 2 = 616 with 0 remainder
616 ÷ 2 = 308 with 0 remainder
308 ÷ 2 = 154 with 0 remainder
154 ÷ 2 = 77 with 0 remainder
77 ÷ 2 = 38 with 1 remainder
38 ÷ 2 = 19 with 0 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 9A08 hexadecimal to binary:

9A08 hexadecimal = 1001101000001000 binary

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9A09 hexadecimal to binary
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