938 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 938 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 938 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 938 by 16⁰, multiply the second to last digit in 938 by 16¹, multiply the third to last digit in 938 by 16², multiply the fourth to last digit in 938 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
3 × 16¹ = 48
9 × 16² = 2304

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 48 + 2304 = 2360

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

2360 ÷ 2 = 1180 with 0 remainder
1180 ÷ 2 = 590 with 0 remainder
590 ÷ 2 = 295 with 0 remainder
295 ÷ 2 = 147 with 1 remainder
147 ÷ 2 = 73 with 1 remainder
73 ÷ 2 = 36 with 1 remainder
36 ÷ 2 = 18 with 0 remainder
18 ÷ 2 = 9 with 0 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 938 hexadecimal to binary:

938 hexadecimal = 100100111000 binary

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939 hexadecimal to binary
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