923B hexadecimal to binary

Here we will show you how to convert the hexadecimal number 923B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 923B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 923B by 16⁰, multiply the second to last digit in 923B by 16¹, multiply the third to last digit in 923B by 16², multiply the fourth to last digit in 923B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
3 × 16¹ = 48
2 × 16² = 512
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 48 + 512 + 36864 = 37435

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

37435 ÷ 2 = 18717 with 1 remainder
18717 ÷ 2 = 9358 with 1 remainder
9358 ÷ 2 = 4679 with 0 remainder
4679 ÷ 2 = 2339 with 1 remainder
2339 ÷ 2 = 1169 with 1 remainder
1169 ÷ 2 = 584 with 1 remainder
584 ÷ 2 = 292 with 0 remainder
292 ÷ 2 = 146 with 0 remainder
146 ÷ 2 = 73 with 0 remainder
73 ÷ 2 = 36 with 1 remainder
36 ÷ 2 = 18 with 0 remainder
18 ÷ 2 = 9 with 0 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 923B hexadecimal to binary:

923B hexadecimal = 1001001000111011 binary

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