920B hexadecimal to binary

Here we will show you how to convert the hexadecimal number 920B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 920B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 920B by 16⁰, multiply the second to last digit in 920B by 16¹, multiply the third to last digit in 920B by 16², multiply the fourth to last digit in 920B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
0 × 16¹ = 0
2 × 16² = 512
9 × 16³ = 36864

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 0 + 512 + 36864 = 37387

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

37387 ÷ 2 = 18693 with 1 remainder
18693 ÷ 2 = 9346 with 1 remainder
9346 ÷ 2 = 4673 with 0 remainder
4673 ÷ 2 = 2336 with 1 remainder
2336 ÷ 2 = 1168 with 0 remainder
1168 ÷ 2 = 584 with 0 remainder
584 ÷ 2 = 292 with 0 remainder
292 ÷ 2 = 146 with 0 remainder
146 ÷ 2 = 73 with 0 remainder
73 ÷ 2 = 36 with 1 remainder
36 ÷ 2 = 18 with 0 remainder
18 ÷ 2 = 9 with 0 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 920B hexadecimal to binary:

920B hexadecimal = 1001001000001011 binary

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