8B53 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 8B53 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 8B53 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 8B53 by 16⁰, multiply the second to last digit in 8B53 by 16¹, multiply the third to last digit in 8B53 by 16², multiply the fourth to last digit in 8B53 by 16³, and so on, until all the digits are used.

3 × 16⁰ = 3
5 × 16¹ = 80
B × 16² = 2816
8 × 16³ = 32768

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

3 + 80 + 2816 + 32768 = 35667

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

35667 ÷ 2 = 17833 with 1 remainder
17833 ÷ 2 = 8916 with 1 remainder
8916 ÷ 2 = 4458 with 0 remainder
4458 ÷ 2 = 2229 with 0 remainder
2229 ÷ 2 = 1114 with 1 remainder
1114 ÷ 2 = 557 with 0 remainder
557 ÷ 2 = 278 with 1 remainder
278 ÷ 2 = 139 with 0 remainder
139 ÷ 2 = 69 with 1 remainder
69 ÷ 2 = 34 with 1 remainder
34 ÷ 2 = 17 with 0 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 8B53 hexadecimal to binary:

8B53 hexadecimal = 1000101101010011 binary

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8B54 hexadecimal to binary
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