7C34 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 7C34 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 7C34 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 7C34 by 16⁰, multiply the second to last digit in 7C34 by 16¹, multiply the third to last digit in 7C34 by 16², multiply the fourth to last digit in 7C34 by 16³, and so on, until all the digits are used.

4 × 16⁰ = 4
3 × 16¹ = 48
C × 16² = 3072
7 × 16³ = 28672

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

4 + 48 + 3072 + 28672 = 31796

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

31796 ÷ 2 = 15898 with 0 remainder
15898 ÷ 2 = 7949 with 0 remainder
7949 ÷ 2 = 3974 with 1 remainder
3974 ÷ 2 = 1987 with 0 remainder
1987 ÷ 2 = 993 with 1 remainder
993 ÷ 2 = 496 with 1 remainder
496 ÷ 2 = 248 with 0 remainder
248 ÷ 2 = 124 with 0 remainder
124 ÷ 2 = 62 with 0 remainder
62 ÷ 2 = 31 with 0 remainder
31 ÷ 2 = 15 with 1 remainder
15 ÷ 2 = 7 with 1 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 7C34 hexadecimal to binary:

7C34 hexadecimal = 111110000110100 binary

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7C35 hexadecimal to binary
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