7B9B hexadecimal to binary

Here we will show you how to convert the hexadecimal number 7B9B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 7B9B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 7B9B by 16⁰, multiply the second to last digit in 7B9B by 16¹, multiply the third to last digit in 7B9B by 16², multiply the fourth to last digit in 7B9B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
9 × 16¹ = 144
B × 16² = 2816
7 × 16³ = 28672

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 144 + 2816 + 28672 = 31643

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

31643 ÷ 2 = 15821 with 1 remainder
15821 ÷ 2 = 7910 with 1 remainder
7910 ÷ 2 = 3955 with 0 remainder
3955 ÷ 2 = 1977 with 1 remainder
1977 ÷ 2 = 988 with 1 remainder
988 ÷ 2 = 494 with 0 remainder
494 ÷ 2 = 247 with 0 remainder
247 ÷ 2 = 123 with 1 remainder
123 ÷ 2 = 61 with 1 remainder
61 ÷ 2 = 30 with 1 remainder
30 ÷ 2 = 15 with 0 remainder
15 ÷ 2 = 7 with 1 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 7B9B hexadecimal to binary:

7B9B hexadecimal = 111101110011011 binary

Hexadecimal to Binary Converter
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