7B4F hexadecimal to binary




Here we will show you how to convert the hexadecimal number 7B4F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert 7B4F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 7B4F by 16⁰, multiply the second to last digit in 7B4F by 16¹, multiply the third to last digit in 7B4F by 16², multiply the fourth to last digit in 7B4F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
4 × 16¹ = 64
B × 16² = 2816
7 × 16³ = 28672

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 64 + 2816 + 28672 = 31567

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

31567 ÷ 2 = 15783 with 1 remainder
15783 ÷ 2 = 7891 with 1 remainder
7891 ÷ 2 = 3945 with 1 remainder
3945 ÷ 2 = 1972 with 1 remainder
1972 ÷ 2 = 986 with 0 remainder
986 ÷ 2 = 493 with 0 remainder
493 ÷ 2 = 246 with 1 remainder
246 ÷ 2 = 123 with 0 remainder
123 ÷ 2 = 61 with 1 remainder
61 ÷ 2 = 30 with 1 remainder
30 ÷ 2 = 15 with 0 remainder
15 ÷ 2 = 7 with 1 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 7B4F hexadecimal to binary:

7B4F hexadecimal = 111101101001111 binary


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