7B0 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 7B0 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 7B0 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 7B0 by 16⁰, multiply the second to last digit in 7B0 by 16¹, multiply the third to last digit in 7B0 by 16², multiply the fourth to last digit in 7B0 by 16³, and so on, until all the digits are used.

0 × 16⁰ = 0
B × 16¹ = 176
7 × 16² = 1792

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

0 + 176 + 1792 = 1968

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

1968 ÷ 2 = 984 with 0 remainder
984 ÷ 2 = 492 with 0 remainder
492 ÷ 2 = 246 with 0 remainder
246 ÷ 2 = 123 with 0 remainder
123 ÷ 2 = 61 with 1 remainder
61 ÷ 2 = 30 with 1 remainder
30 ÷ 2 = 15 with 0 remainder
15 ÷ 2 = 7 with 1 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 7B0 hexadecimal to binary:

7B0 hexadecimal = 11110110000 binary

Hexadecimal to Binary Converter
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7B1 hexadecimal to binary
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