7A83 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 7A83 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 7A83 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 7A83 by 16⁰, multiply the second to last digit in 7A83 by 16¹, multiply the third to last digit in 7A83 by 16², multiply the fourth to last digit in 7A83 by 16³, and so on, until all the digits are used.

3 × 16⁰ = 3
8 × 16¹ = 128
A × 16² = 2560
7 × 16³ = 28672

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

3 + 128 + 2560 + 28672 = 31363

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

31363 ÷ 2 = 15681 with 1 remainder
15681 ÷ 2 = 7840 with 1 remainder
7840 ÷ 2 = 3920 with 0 remainder
3920 ÷ 2 = 1960 with 0 remainder
1960 ÷ 2 = 980 with 0 remainder
980 ÷ 2 = 490 with 0 remainder
490 ÷ 2 = 245 with 0 remainder
245 ÷ 2 = 122 with 1 remainder
122 ÷ 2 = 61 with 0 remainder
61 ÷ 2 = 30 with 1 remainder
30 ÷ 2 = 15 with 0 remainder
15 ÷ 2 = 7 with 1 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 7A83 hexadecimal to binary:

7A83 hexadecimal = 111101010000011 binary

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7A84 hexadecimal to binary
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