6C5A hexadecimal to binary

Here we will show you how to convert the hexadecimal number 6C5A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 6C5A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 6C5A by 16⁰, multiply the second to last digit in 6C5A by 16¹, multiply the third to last digit in 6C5A by 16², multiply the fourth to last digit in 6C5A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
5 × 16¹ = 80
C × 16² = 3072
6 × 16³ = 24576

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 80 + 3072 + 24576 = 27738

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

27738 ÷ 2 = 13869 with 0 remainder
13869 ÷ 2 = 6934 with 1 remainder
6934 ÷ 2 = 3467 with 0 remainder
3467 ÷ 2 = 1733 with 1 remainder
1733 ÷ 2 = 866 with 1 remainder
866 ÷ 2 = 433 with 0 remainder
433 ÷ 2 = 216 with 1 remainder
216 ÷ 2 = 108 with 0 remainder
108 ÷ 2 = 54 with 0 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 6C5A hexadecimal to binary:

6C5A hexadecimal = 110110001011010 binary

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6C5B hexadecimal to binary
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