6B80 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 6B80 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 6B80 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 6B80 by 16⁰, multiply the second to last digit in 6B80 by 16¹, multiply the third to last digit in 6B80 by 16², multiply the fourth to last digit in 6B80 by 16³, and so on, until all the digits are used.

0 × 16⁰ = 0
8 × 16¹ = 128
B × 16² = 2816
6 × 16³ = 24576

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

0 + 128 + 2816 + 24576 = 27520

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

27520 ÷ 2 = 13760 with 0 remainder
13760 ÷ 2 = 6880 with 0 remainder
6880 ÷ 2 = 3440 with 0 remainder
3440 ÷ 2 = 1720 with 0 remainder
1720 ÷ 2 = 860 with 0 remainder
860 ÷ 2 = 430 with 0 remainder
430 ÷ 2 = 215 with 0 remainder
215 ÷ 2 = 107 with 1 remainder
107 ÷ 2 = 53 with 1 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 6B80 hexadecimal to binary:

6B80 hexadecimal = 110101110000000 binary

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6B81 hexadecimal to binary
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