6B38 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 6B38 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 6B38 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 6B38 by 16⁰, multiply the second to last digit in 6B38 by 16¹, multiply the third to last digit in 6B38 by 16², multiply the fourth to last digit in 6B38 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
3 × 16¹ = 48
B × 16² = 2816
6 × 16³ = 24576

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 48 + 2816 + 24576 = 27448

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

27448 ÷ 2 = 13724 with 0 remainder
13724 ÷ 2 = 6862 with 0 remainder
6862 ÷ 2 = 3431 with 0 remainder
3431 ÷ 2 = 1715 with 1 remainder
1715 ÷ 2 = 857 with 1 remainder
857 ÷ 2 = 428 with 1 remainder
428 ÷ 2 = 214 with 0 remainder
214 ÷ 2 = 107 with 0 remainder
107 ÷ 2 = 53 with 1 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 6B38 hexadecimal to binary:

6B38 hexadecimal = 110101100111000 binary

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6B39 hexadecimal to binary
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