
Here we will show you how to convert the hexadecimal number 58D8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).
The four steps used to convert 58D8 from hexadecimal to binary are explained below.
Step 1)
Multiply the last digit in 58D8 by 16⁰, multiply the second to last digit in 58D8 by 16¹, multiply the third to last digit in 58D8 by 16², multiply the fourth to last digit in 58D8 by 16³, and so on, until all the digits are used.
8 × 16⁰ = 8
D × 16¹ = 208
8 × 16² = 2048
5 × 16³ = 20480
Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.
Step 2)
Next, we add up all the products we got from Step 1, like this:
8 + 208 + 2048 + 20480 = 22744
Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.
22744 ÷ 2 = 11372 with 0 remainder
11372 ÷ 2 = 5686 with 0 remainder
5686 ÷ 2 = 2843 with 0 remainder
2843 ÷ 2 = 1421 with 1 remainder
1421 ÷ 2 = 710 with 1 remainder
710 ÷ 2 = 355 with 0 remainder
355 ÷ 2 = 177 with 1 remainder
177 ÷ 2 = 88 with 1 remainder
88 ÷ 2 = 44 with 0 remainder
44 ÷ 2 = 22 with 0 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder
Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 58D8 hexadecimal to binary:
58D8 hexadecimal = 101100011011000 binary
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58D9 hexadecimal to binary
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