547C hexadecimal to binary

Here we will show you how to convert the hexadecimal number 547C to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 547C from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 547C by 16⁰, multiply the second to last digit in 547C by 16¹, multiply the third to last digit in 547C by 16², multiply the fourth to last digit in 547C by 16³, and so on, until all the digits are used.

C × 16⁰ = 12
7 × 16¹ = 112
4 × 16² = 1024
5 × 16³ = 20480

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

12 + 112 + 1024 + 20480 = 21628

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

21628 ÷ 2 = 10814 with 0 remainder
10814 ÷ 2 = 5407 with 0 remainder
5407 ÷ 2 = 2703 with 1 remainder
2703 ÷ 2 = 1351 with 1 remainder
1351 ÷ 2 = 675 with 1 remainder
675 ÷ 2 = 337 with 1 remainder
337 ÷ 2 = 168 with 1 remainder
168 ÷ 2 = 84 with 0 remainder
84 ÷ 2 = 42 with 0 remainder
42 ÷ 2 = 21 with 0 remainder
21 ÷ 2 = 10 with 1 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 547C hexadecimal to binary:

547C hexadecimal = 101010001111100 binary

Hexadecimal to Binary Converter
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