530A hexadecimal to binary

Here we will show you how to convert the hexadecimal number 530A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 530A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 530A by 16⁰, multiply the second to last digit in 530A by 16¹, multiply the third to last digit in 530A by 16², multiply the fourth to last digit in 530A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
0 × 16¹ = 0
3 × 16² = 768
5 × 16³ = 20480

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 0 + 768 + 20480 = 21258

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

21258 ÷ 2 = 10629 with 0 remainder
10629 ÷ 2 = 5314 with 1 remainder
5314 ÷ 2 = 2657 with 0 remainder
2657 ÷ 2 = 1328 with 1 remainder
1328 ÷ 2 = 664 with 0 remainder
664 ÷ 2 = 332 with 0 remainder
332 ÷ 2 = 166 with 0 remainder
166 ÷ 2 = 83 with 0 remainder
83 ÷ 2 = 41 with 1 remainder
41 ÷ 2 = 20 with 1 remainder
20 ÷ 2 = 10 with 0 remainder
10 ÷ 2 = 5 with 0 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 530A hexadecimal to binary:

530A hexadecimal = 101001100001010 binary

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530B hexadecimal to binary
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