4D38 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 4D38 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 4D38 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 4D38 by 16⁰, multiply the second to last digit in 4D38 by 16¹, multiply the third to last digit in 4D38 by 16², multiply the fourth to last digit in 4D38 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
3 × 16¹ = 48
D × 16² = 3328
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 48 + 3328 + 16384 = 19768

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

19768 ÷ 2 = 9884 with 0 remainder
9884 ÷ 2 = 4942 with 0 remainder
4942 ÷ 2 = 2471 with 0 remainder
2471 ÷ 2 = 1235 with 1 remainder
1235 ÷ 2 = 617 with 1 remainder
617 ÷ 2 = 308 with 1 remainder
308 ÷ 2 = 154 with 0 remainder
154 ÷ 2 = 77 with 0 remainder
77 ÷ 2 = 38 with 1 remainder
38 ÷ 2 = 19 with 0 remainder
19 ÷ 2 = 9 with 1 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 4D38 hexadecimal to binary:

4D38 hexadecimal = 100110100111000 binary

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4D39 hexadecimal to binary
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