4B08 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 4B08 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 4B08 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 4B08 by 16⁰, multiply the second to last digit in 4B08 by 16¹, multiply the third to last digit in 4B08 by 16², multiply the fourth to last digit in 4B08 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
0 × 16¹ = 0
B × 16² = 2816
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 0 + 2816 + 16384 = 19208

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

19208 ÷ 2 = 9604 with 0 remainder
9604 ÷ 2 = 4802 with 0 remainder
4802 ÷ 2 = 2401 with 0 remainder
2401 ÷ 2 = 1200 with 1 remainder
1200 ÷ 2 = 600 with 0 remainder
600 ÷ 2 = 300 with 0 remainder
300 ÷ 2 = 150 with 0 remainder
150 ÷ 2 = 75 with 0 remainder
75 ÷ 2 = 37 with 1 remainder
37 ÷ 2 = 18 with 1 remainder
18 ÷ 2 = 9 with 0 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 4B08 hexadecimal to binary:

4B08 hexadecimal = 100101100001000 binary

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