
Here we will show you how to convert the hexadecimal number 497F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).
The four steps used to convert 497F from hexadecimal to binary are explained below.
Step 1)
Multiply the last digit in 497F by 16⁰, multiply the second to last digit in 497F by 16¹, multiply the third to last digit in 497F by 16², multiply the fourth to last digit in 497F by 16³, and so on, until all the digits are used.
F × 16⁰ = 15
7 × 16¹ = 112
9 × 16² = 2304
4 × 16³ = 16384
Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.
Step 2)
Next, we add up all the products we got from Step 1, like this:
15 + 112 + 2304 + 16384 = 18815
Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.
18815 ÷ 2 = 9407 with 1 remainder
9407 ÷ 2 = 4703 with 1 remainder
4703 ÷ 2 = 2351 with 1 remainder
2351 ÷ 2 = 1175 with 1 remainder
1175 ÷ 2 = 587 with 1 remainder
587 ÷ 2 = 293 with 1 remainder
293 ÷ 2 = 146 with 1 remainder
146 ÷ 2 = 73 with 0 remainder
73 ÷ 2 = 36 with 1 remainder
36 ÷ 2 = 18 with 0 remainder
18 ÷ 2 = 9 with 0 remainder
9 ÷ 2 = 4 with 1 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder
Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 497F hexadecimal to binary:
497F hexadecimal = 100100101111111 binary
Hexadecimal to Binary Converter
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