47E8 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 47E8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 47E8 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 47E8 by 16⁰, multiply the second to last digit in 47E8 by 16¹, multiply the third to last digit in 47E8 by 16², multiply the fourth to last digit in 47E8 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
E × 16¹ = 224
7 × 16² = 1792
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 224 + 1792 + 16384 = 18408

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

18408 ÷ 2 = 9204 with 0 remainder
9204 ÷ 2 = 4602 with 0 remainder
4602 ÷ 2 = 2301 with 0 remainder
2301 ÷ 2 = 1150 with 1 remainder
1150 ÷ 2 = 575 with 0 remainder
575 ÷ 2 = 287 with 1 remainder
287 ÷ 2 = 143 with 1 remainder
143 ÷ 2 = 71 with 1 remainder
71 ÷ 2 = 35 with 1 remainder
35 ÷ 2 = 17 with 1 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 47E8 hexadecimal to binary:

47E8 hexadecimal = 100011111101000 binary

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47E9 hexadecimal to binary
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