47C6 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 47C6 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 47C6 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 47C6 by 16⁰, multiply the second to last digit in 47C6 by 16¹, multiply the third to last digit in 47C6 by 16², multiply the fourth to last digit in 47C6 by 16³, and so on, until all the digits are used.

6 × 16⁰ = 6
C × 16¹ = 192
7 × 16² = 1792
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

6 + 192 + 1792 + 16384 = 18374

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

18374 ÷ 2 = 9187 with 0 remainder
9187 ÷ 2 = 4593 with 1 remainder
4593 ÷ 2 = 2296 with 1 remainder
2296 ÷ 2 = 1148 with 0 remainder
1148 ÷ 2 = 574 with 0 remainder
574 ÷ 2 = 287 with 0 remainder
287 ÷ 2 = 143 with 1 remainder
143 ÷ 2 = 71 with 1 remainder
71 ÷ 2 = 35 with 1 remainder
35 ÷ 2 = 17 with 1 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 47C6 hexadecimal to binary:

47C6 hexadecimal = 100011111000110 binary

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47C7 hexadecimal to binary
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