47B6 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 47B6 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 47B6 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 47B6 by 16⁰, multiply the second to last digit in 47B6 by 16¹, multiply the third to last digit in 47B6 by 16², multiply the fourth to last digit in 47B6 by 16³, and so on, until all the digits are used.

6 × 16⁰ = 6
B × 16¹ = 176
7 × 16² = 1792
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

6 + 176 + 1792 + 16384 = 18358

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

18358 ÷ 2 = 9179 with 0 remainder
9179 ÷ 2 = 4589 with 1 remainder
4589 ÷ 2 = 2294 with 1 remainder
2294 ÷ 2 = 1147 with 0 remainder
1147 ÷ 2 = 573 with 1 remainder
573 ÷ 2 = 286 with 1 remainder
286 ÷ 2 = 143 with 0 remainder
143 ÷ 2 = 71 with 1 remainder
71 ÷ 2 = 35 with 1 remainder
35 ÷ 2 = 17 with 1 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 47B6 hexadecimal to binary:

47B6 hexadecimal = 100011110110110 binary

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47B7 hexadecimal to binary
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