47A4 hexadecimal to binary

Here we will show you how to convert the hexadecimal number 47A4 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 47A4 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 47A4 by 16⁰, multiply the second to last digit in 47A4 by 16¹, multiply the third to last digit in 47A4 by 16², multiply the fourth to last digit in 47A4 by 16³, and so on, until all the digits are used.

4 × 16⁰ = 4
A × 16¹ = 160
7 × 16² = 1792
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

4 + 160 + 1792 + 16384 = 18340

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

18340 ÷ 2 = 9170 with 0 remainder
9170 ÷ 2 = 4585 with 0 remainder
4585 ÷ 2 = 2292 with 1 remainder
2292 ÷ 2 = 1146 with 0 remainder
1146 ÷ 2 = 573 with 0 remainder
573 ÷ 2 = 286 with 1 remainder
286 ÷ 2 = 143 with 0 remainder
143 ÷ 2 = 71 with 1 remainder
71 ÷ 2 = 35 with 1 remainder
35 ÷ 2 = 17 with 1 remainder
17 ÷ 2 = 8 with 1 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 47A4 hexadecimal to binary:

47A4 hexadecimal = 100011110100100 binary

Hexadecimal to Binary Converter
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47A5 hexadecimal to binary
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