428F hexadecimal to binary

Here we will show you how to convert the hexadecimal number 428F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 428F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 428F by 16⁰, multiply the second to last digit in 428F by 16¹, multiply the third to last digit in 428F by 16², multiply the fourth to last digit in 428F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
8 × 16¹ = 128
2 × 16² = 512
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 128 + 512 + 16384 = 17039

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

17039 ÷ 2 = 8519 with 1 remainder
8519 ÷ 2 = 4259 with 1 remainder
4259 ÷ 2 = 2129 with 1 remainder
2129 ÷ 2 = 1064 with 1 remainder
1064 ÷ 2 = 532 with 0 remainder
532 ÷ 2 = 266 with 0 remainder
266 ÷ 2 = 133 with 0 remainder
133 ÷ 2 = 66 with 1 remainder
66 ÷ 2 = 33 with 0 remainder
33 ÷ 2 = 16 with 1 remainder
16 ÷ 2 = 8 with 0 remainder
8 ÷ 2 = 4 with 0 remainder
4 ÷ 2 = 2 with 0 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 428F hexadecimal to binary:

428F hexadecimal = 100001010001111 binary

Hexadecimal to Binary Converter
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