38C7 hexadecimal to binary




Here we will show you how to convert the hexadecimal number 38C7 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert 38C7 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in 38C7 by 16⁰, multiply the second to last digit in 38C7 by 16¹, multiply the third to last digit in 38C7 by 16², multiply the fourth to last digit in 38C7 by 16³, and so on, until all the digits are used.

7 × 16⁰ = 7
C × 16¹ = 192
8 × 16² = 2048
3 × 16³ = 12288

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

7 + 192 + 2048 + 12288 = 14535

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

14535 ÷ 2 = 7267 with 1 remainder
7267 ÷ 2 = 3633 with 1 remainder
3633 ÷ 2 = 1816 with 1 remainder
1816 ÷ 2 = 908 with 0 remainder
908 ÷ 2 = 454 with 0 remainder
454 ÷ 2 = 227 with 0 remainder
227 ÷ 2 = 113 with 1 remainder
113 ÷ 2 = 56 with 1 remainder
56 ÷ 2 = 28 with 0 remainder
28 ÷ 2 = 14 with 0 remainder
14 ÷ 2 = 7 with 0 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 38C7 hexadecimal to binary:

38C7 hexadecimal = 11100011000111 binary


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